Is half correct; Using the meter on the ohms setting as a tiny little battery charger is not a test for the capacitors resistance. It's the voltage that he is wanting to measure a change in, the resistance of the cap does not change, if your cap holds a measurable voltage it is probably good, if you can never get it to take on a measurable charge (voltage) it is possibly cooked.My understanding was that when switched to the ohms setting, a multimeter uses battery power to force current through the circuit, and the resistance should increase as the capacitor charges. If it never rises from zero, it's not charging. Is this not correct?
resistance is futile
Have you got it going yet?